UPSC Mathematics Optional · Paper II · Analytic Functions to Residues
\(z=x+iy=re^{i\theta}\). \(|z|=r=\sqrt{x^2+y^2}\). \(\arg z=\theta=\arctan(y/x)\).
\(\bar z=x-iy\). \(|z|^2=z\bar z\). \(\text{Re}(z)=\frac{z+\bar z}{2}\). \(\text{Im}(z)=\frac{z-\bar z}{2i}\).
de Moivre: \((\cos\theta+i\sin\theta)^n=\cos n\theta+i\sin n\theta\).
Euler: \(e^{i\theta}=\cos\theta+i\sin\theta\). Hence \(e^{i\pi}+1=0\).
Triangle inequality: \(|z_1+z_2|\le|z_1|+|z_2|\). \(\big||z_1|-|z_2|\big|\le|z_1-z_2|\).
nth roots of \(re^{i\theta}\): \(r^{1/n}e^{i(\theta+2k\pi)/n}\), \(k=0,1,\ldots,n-1\).
nth roots of unity: \(e^{2\pi ik/n}\), \(k=0,\ldots,n-1\). Sum = 0.
\(f(z)\) is analytic at \(z_0\) if it is differentiable in some neighbourhood of \(z_0\).
\(f'(z_0)=\lim_{\Delta z\to 0}\dfrac{f(z_0+\Delta z)-f(z_0)}{\Delta z}\) (limit must be same from all directions).
If \(f(z)=u(x,y)+iv(x,y)\) is differentiable at \(z=x+iy\), then:
\[\frac{\partial u}{\partial x}=\frac{\partial v}{\partial y},\qquad\frac{\partial u}{\partial y}=-\frac{\partial v}{\partial x}\]
Sufficient condition: If \(u,v\) have continuous partial derivatives satisfying CR equations, then \(f\) is analytic.
\(f'(z)=u_x+iv_x=u_x-iu_y=v_y+iv_x\).
Polar form: \(u_r=\dfrac{1}{r}v_\theta\), \(v_r=-\dfrac{1}{r}u_\theta\).
If \(f=u+iv\) is analytic, then \(u\) and \(v\) are both harmonic: \(\nabla^2 u=0\), \(\nabla^2 v=0\).
Level curves of \(u\) and \(v\) intersect orthogonally.
Finding \(v\) given \(u\): Use \(v_x=-u_y\), \(v_y=u_x\); integrate.
Milne-Thomson method: \(f(z)=\phi(z,0)-i\int\phi_1(z,0)dz\) where \(\phi_1=\partial u/\partial x\Big|_{y=0}\).
\(\displaystyle\int_C f(z)\,dz=\int_a^b f(z(t))z'(t)\,dt\)
where \(z=z(t)\), \(t\in[a,b]\) parametrizes \(C\).
Bound: \(\left|\int_C f\,dz\right|\le ML\) where \(M=\max|f|\) on \(C\), \(L=\) length of \(C\) (ML-inequality).
If \(f\) is analytic in a simply connected domain \(D\), then \(\oint_C f(z)\,dz=0\) for every closed contour \(C\) in \(D\).
Independence of path: The integral depends only on endpoints.
\[f(z_0)=\frac{1}{2\pi i}\oint_C\frac{f(z)}{z-z_0}\,dz\]
Generalized: \[f^{(n)}(z_0)=\frac{n!}{2\pi i}\oint_C\frac{f(z)}{(z-z_0)^{n+1}}\,dz\]
Consequence: Analytic functions are infinitely differentiable (holomorphic ⟺ analytic as power series).
Liouville: A bounded entire function is constant.
Fundamental Theorem of Algebra: Every non-constant polynomial has a root in \(\mathbb{C}\).
Maximum Modulus Principle: If \(f\) analytic and non-constant in domain \(D\), then \(|f|\) attains no maximum in the interior of \(D\).
If \(f\) analytic in \(|z-z_0|
If \(f\) analytic in annulus \(r<|z-z_0| \[f(z)=\sum_{n=-\infty}^{\infty}a_n(z-z_0)^n, \quad a_n=\frac{1}{2\pi i}\oint_C\frac{f(z)}{(z-z_0)^{n+1}}\,dz\] Principal part: terms with negative powers. Analytic part: non-negative powers.
Residue of \(f\) at \(z_0\) = coefficient \(a_{-1}\) in Laurent expansion.
\[\oint_C f(z)\,dz=2\pi i\sum_k\text{Res}(f,z_k)\]
where the sum is over all singularities \(z_k\) inside \(C\). \(C\) positively oriented.
Type 1: \(\displaystyle\int_0^{2\pi} R(\cos\theta,\sin\theta)\,d\theta\). Put \(z=e^{i\theta}\): \(\cos\theta=\dfrac{z+z^{-1}}{2}\), \(\sin\theta=\dfrac{z-z^{-1}}{2i}\), \(d\theta=\dfrac{dz}{iz}\).
Type 2: \(\displaystyle\int_{-\infty}^\infty \frac{P(x)}{Q(x)}\,dx=2\pi i\sum\text{Res in upper half-plane}\).
Condition: \(\deg Q\ge\deg P+2\), \(Q\) has no real zeros.
Type 3: \(\displaystyle\int_{-\infty}^\infty \frac{P(x)}{Q(x)}e^{imx}\,dx\): close in UHP if \(m>0\), LHP if \(m<0\) (Jordan's lemma).
Jordan's Lemma: \(\int_{C_R}f(z)e^{iaz}\,dz\to 0\) as \(R\to\infty\) if \(a>0\) and \(|f(z)|\to 0\) on upper semicircle.
If \(f\) has a simple pole at \(x_0\in\mathbb{R}\): indent with small semicircle of radius \(\varepsilon\). Contribution = \(\pm\pi i\cdot\text{Res}(f,x_0)\) (sign depends on direction: \(-\pi i\) going above, \(+\pi i\) going below).
\(w=\dfrac{az+b}{cz+d}\), \(ad-bc\ne 0\).
An analytic function \(f\) is conformal at \(z_0\) if \(f'(z_0)\ne 0\): preserves angles between curves.
Key mappings:
Any simply connected domain \(\Omega\ne\mathbb{C}\) is conformally equivalent to the unit disk. (Existence only — not constructive.)