UPSC Mathematics Optional · Paper I · Theorems, Formulae & PYQ Insights
A set \(V\) with addition and scalar multiplication (over field \(F\)) satisfying 8 axioms: commutativity, associativity, identity (\(\mathbf{0}\)), inverse, distributivity (×2), associativity of scalar mult., unit scalar.
\(W \subseteq V\) is a subspace iff: (i) \(\mathbf{0}\in W\), (ii) closed under addition, (iii) closed under scalar multiplication.
Equivalently: \(\alpha u + \beta v \in W\) for all \(u,v\in W\), \(\alpha,\beta\in F\).
\[\dim(U+W) = \dim U + \dim W - \dim(U\cap W)\]
\(T:V\to W\) is linear iff \(T(\alpha u+\beta v)=\alpha T(u)+\beta T(v)\).
Completely determined by images of basis vectors.
\[\text{rank}(T) + \text{nullity}(T) = \dim V\]
i.e. \(\dim(\text{Im}\,T) + \dim(\ker T) = \dim V\).
Matrix form: rank\((A)\) + nullity\((A)\) = number of columns of \(A\).
If \(\mathcal{B}=\{v_1,\ldots,v_n\}\) is a basis of \(V\) and \(\mathcal{C}\) of \(W\), the matrix \([T]_{\mathcal{B}}^{\mathcal{C}}\) has columns = coordinates of \(T(v_j)\) in basis \(\mathcal{C}\).
Change of basis: \([T]_{\mathcal{B}'} = P^{-1}[T]_{\mathcal{B}}P\) where \(P\) = transition matrix.
Two finite-dimensional vector spaces over the same field are isomorphic iff they have the same dimension.
\(T:V\to W\) is an isomorphism iff \(T\) is bijective iff \(\ker T = \{0\}\) and \(\text{Im}\,T = W\).
\[A^{-1} = \frac{1}{\det A}\,\text{adj}(A)\]
where \(\text{adj}(A)_{ij} = (-1)^{i+j}M_{ji}\) (\(M_{ji}\) = minor of \(a_{ji}\)).
\(A\cdot\text{adj}(A) = (\det A)\,I\)
\(\text{tr}(A) = \sum_i a_{ii} = \sum_i \lambda_i\) (sum of eigenvalues).
\(\text{tr}(AB)=\text{tr}(BA)\). \(\text{tr}(A+B)=\text{tr}A+\text{tr}B\).
The system \(AX=B\) is consistent iff \(\text{rank}(A) = \text{rank}([A|B])\).
Always consistent (trivial solution \(X=0\)).
Non-trivial solution exists iff \(\text{rank}(A) < n\) iff \(\det A = 0\).
Solution space (null space) has dimension \(n - \text{rank}(A)\).
For \(AX=B\) with \(\det A \ne 0\): \(x_i = \dfrac{\det A_i}{\det A}\), where \(A_i\) = \(A\) with \(i\)-th column replaced by \(B\).
\(\det(A - \lambda I) = 0\) gives the characteristic polynomial \(p(\lambda)\).
Eigenvalues = roots of \(p(\lambda)\). Eigenvectors: solve \((A-\lambda I)X=0\).
Every square matrix satisfies its own characteristic equation.
If \(p(\lambda) = \det(\lambda I - A)\), then \(p(A) = 0\).
Use: Find \(A^{-1}\), higher powers of \(A\), minimal polynomial.
For \(2\times 2\): \(A^2 - (\text{tr}\,A)\,A + (\det A)\,I = 0\)
Rearranging: \(A^{-1} = \dfrac{1}{\det A}[(\text{tr}\,A)\,I - A]\)
For \(3\times 3\) with char. poly \(\lambda^3-p\lambda^2+q\lambda-r=0\):
\(A^3 - pA^2 + qA - rI = 0 \Rightarrow A^{-1} = \tfrac{1}{r}(A^2-pA+qI)\)
The monic polynomial of least degree that \(A\) satisfies. It divides the characteristic polynomial. Eigenvalues of \(A\) = roots of minimal polynomial.
If all eigenvalues are distinct, minimal poly = characteristic poly.
\(A\) is diagonalizable iff it has \(n\) linearly independent eigenvectors iff for each eigenvalue \(\lambda_i\), geometric multiplicity = algebraic multiplicity.
If diagonalizable: \(A = PDP^{-1}\) where \(D=\text{diag}(\lambda_1,\ldots,\lambda_n)\), columns of \(P\) = eigenvectors.
Then: \(A^n = PD^nP^{-1}\), \(f(A)=Pf(D)P^{-1}\).
Every real symmetric matrix is orthogonally diagonalizable: \(A = Q\Lambda Q^T\) where \(Q\) is orthogonal (columns = orthonormal eigenvectors) and \(\Lambda\) = diagonal matrix of eigenvalues.
If some eigenvalue has algebraic multiplicity \(>\) geometric multiplicity. Then we need Jordan Normal Form. Jordan block for eigenvalue \(\lambda\) of size \(k\): \(\lambda\) on diagonal, 1's on superdiagonal.
\(\langle\cdot,\cdot\rangle:V\times V\to\mathbb{R}\) (or \(\mathbb{C}\)) satisfying: linearity in first argument, conjugate symmetry, positive definiteness.
\(\|v\| = \sqrt{\langle v,v\rangle}\). Angle: \(\cos\theta = \dfrac{\langle u,v\rangle}{\|u\|\|v\|}\).
\[|\langle u,v\rangle| \le \|u\|\,\|v\|\]
Equality iff \(u\) and \(v\) are linearly dependent.
Given basis \(\{v_1,\ldots,v_n\}\), construct orthonormal basis \(\{e_1,\ldots,e_n\}\):
\[u_1 = v_1,\quad u_k = v_k - \sum_{j=1}^{k-1}\frac{\langle v_k,u_j\rangle}{\langle u_j,u_j\rangle}u_j,\quad e_k = \frac{u_k}{\|u_k\|}\]
\(W^\perp = \{v\in V : \langle v,w\rangle=0\;\forall w\in W\}\).
\(V = W \oplus W^\perp\). \(\dim W + \dim W^\perp = \dim V\).
Projection of \(v\) onto \(W\): \(\text{proj}_W v = \sum_i \langle v,e_i\rangle e_i\) (orthonormal basis \(\{e_i\}\) of \(W\)).
\(Q(\mathbf{x}) = \mathbf{x}^T A \mathbf{x}\) where \(A\) is symmetric. \(Q = \sum_{i,j} a_{ij}x_ix_j\).
Canonical form: Under orthogonal transformation, \(Q = \lambda_1 y_1^2 + \cdots + \lambda_n y_n^2\).
The number of positive, negative, and zero eigenvalues (the signature \((p,q,r)\)) is invariant under congruence transformations.
Index = \(p\) (number of positive eigenvalues). Rank = \(p+q\).